# How do you construct the perpendicular bisector of a line segment by paper folding?

## How do you construct the perpendicular bisector of a line segment by paper folding?

Procedure

1. Take a square sheet of tracing paper and draw a line segment PQ of desired length as shown in fig. (i).
2. Fold this sheet along the middle in such a way that point P falls on point Q fig. (ii).
3. Press the paper properly, so that a crease is obtained. Unfold the paper and draw the dotted line over the crease.

## How do you construct a perpendicular bisector of a segment?

The perpendicular bisector of a line segment

1. open the compass more than half of the distance between A and B, and scribe arcs of the same radius centered at A and B.
2. Call the two points where these two arcs meet C and D. Draw the line between C and D.
3. CD is the perpendicular bisector of the line segment AB.
4. Proof.

How many perpendicular bisectors can be drawn to a line?

one perpendicular bisector
Only one perpendicular bisector can be drawn to a given line segment.

What are the steps in constructing perpendicular and parallel lines?

Constructing perpendicular and parallel lines

1. Step 1: Draw a perpendicular line between A and XY.
2. Step 2: Measure the perpendicular distance between the point and the line.
3. Step 3: Draw a point that is the same distance from the line.
4. Step 4: Draw the parallel line.

### What is paper folding method?

: the art or process of folding squares of colored paper into representative shapes — see origami.

### What is paper folding activity?

Share This. Rationale: When in a conflict situation, parties to the conflict can become convinced that their truth is the one and only truth. This exercise encourages participants to consider that one experience may lead to multiple interpretations.

How do you construct a perpendicular bisector of 6 cm?

Draw the perpendicular bisector of the line segment AB= 6 cm .

1. Draw a line segment AB=6 cm.
2. With A as the centre and more than half of AB as the radius, draw tow arcs on either side of ¯AB.
3. With B as the centre and with the same radius, draw two arcs which intersect the previous arcs at X and Y.
4. Join XY.

How do you construct a perpendicular line through a point?

How to Construct a Perpendicular Line through a Point on the Given Line?

1. Open the compass to a radius less than half the segment.
2. Draw two arcs intersecting the line on both sides of the point.
3. Draw two arcs using the intersection points as the centers.
4. Construct a line between this point and the original point.

## Which paper folding method can be used to form a midpoint of a line segment?

To construct the midpoint of a line segment, start by drawing a line segment on the patty paper. Next, fold the paper so that the endpoints of the line segment overlap. This creates a crease in the paper. The intersection of the crease and the original line segment is the midpoint of the line segment.

## What are the steps to bisecting an angle?

Construction: bisect ∠ABC.

1. STEPS:
2. Place compass point on the vertex of the angle (point B).
3. Stretch the compass to any length that will stay ON the angle.
4. Swing an arc so the pencil crosses both sides (rays) of the given angle.
5. Place the compass point on one of these new intersection points on the sides of the angle.

How to draw the perpendicular bisector of a line segment?

Join C and D to get the perpendicular bisector of the given line segment AB. In the above figure, CD is the perpendicular bisector of the line segment AB. This construction clearly shows how to draw the perpendicular bisector of a given line segment with compass and straightedge or ruler.

How to construct a perpendicular from a line?

Perpendicular bisector of a line segment Perpendicular from a line at a point Perpendicular from a line through a point Perpendicular from endpoint of a ray Divide a segment into n equal parts Parallel line through a point (angle copy) Parallel line through a point (rhombus)

### How to bisect a segment with compass and straightedge or?

Proof Argument Reason 1 Line segments AP, AQ, PB, QB are all con The four distances were all drawn with t 2 Triangles ∆APQ and ∆BPQ are isosceles Two sides are congruent(length c) 3 Angles AQJ, APJ are congruent Base angles of isoscelestriangl

### How to divide a line segment into n equal parts?

Difference of two line segments Perpendicular bisector of a line segment Perpendicular from a line at a point Perpendicular from a line through a point Perpendicular from endpoint of a ray Divide a segment into n equal parts Parallel line through a point (angle copy)