What is the smallest positive integer divisible by every positive integer less than or equal to 10?

What is the smallest positive integer divisible by every positive integer less than or equal to 10?

2520 is: the smallest number divisible by all integers from 1 to 10, i.e., it is their least common multiple. half of 7!

What is the smallest positive number divisible by 2 5 and 10?

2520 is the smallest positive number divisible by every integers from 2 to 10.

What is the smallest positive integer with 10 factors?

The required smallest number with 10 different factors is 72.

Which integer is the smallest positive integer?

number 1
So, the number 1 is the smallest positive integer.

What is the least positive integer divisible by the four smallest odd positive integers?

10. What is the least positive integer divisible by the four smallest odd, positive integer? The four smallest positive odd integers are 1, 3, 5 and 7. All of these numbers are prime, so their least common multiple is the product of all four numbers or 1 · 3 · 5 · 7 = 105.

Which of the following numbers is divisible by 12?

Factors of 12 are 1, 2,3,4,6, and 12. So the number 12 will be divisible by 1,2,3,4,6 and 12.

Which is smallest integer?

zero
The smallest integer is zero.

Is 0 considered an integer?

As a whole number that can be written without a remainder, 0 classifies as an integer.

Which is the smallest number that can be divided by all of the numbers?

Problem 5: 2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

How is a number divisible by its prime factors?

Now if a number is divisible by X it will be divisible by its prime factors also. So if a number is divisible by 20 it will be divisible by its prime factors. And there are 8 prime factors under 20.

Is the GCD of two positive numbers larger than the smaller of two?

You are looping until you reach the larger of the two arguments. Since the cumulative LCMs grow rather fast, that takes a lot of time. But the GCD (or HCF, if you prefer) of two (positive) numbers cannot be larger than the smaller of the two.

How to find the greatest common divisor of a number?

You’re searching for the Greatest Common Divisor (gcd) of the answer and the next number in your sequence (similar to a bubble sort). You could just check to see if your current answer is divisible by the next factor and if not then add your current answer to itself until the answer is divisible by the next factor.