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What is the formula and oxidation number for phosphate?

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What is the formula and oxidation number for phosphate?

In the phosphate ion, the oxidation number of phosphorous is+5. The sum of the oxidation numbers in PO43-, a polyatomic ion, is -3, the charge of the ion. We assign -2 as the oxidation number of each O and x as the oxidation number of P and write the following equation: x + 4(-2) = -3…. x = +5.

What is the oxidation state of P in PO4?

+5
In the given polyatomic anion, we have to find the oxidation number of P. We know that the charge on an oxygen atom is −2. Thus, the oxidation number of P in PO3−4 is +5. We are given a polyatomic anion SO2−4.

What is the oxidation number of phosphorus in P?

Hydrogen is present with an oxidation state of +1 each. Oxygen is present with an oxidation state of -2 each. The molecule has no net charge. Therefore, to balance, the phosphorus (P) atom must have an oxidation state of +5.

What is the oxidation number of NaH2PO4?

Thus , oxidation number of P in NaH2PO4​ is + 5 .

Can phosphate be oxidized?

Key Concepts and Summary. Phosphorus (group 15) commonly exhibits oxidation states of 3- with active metals and of 3+ and 5+ with more electronegative nonmetals. The halogens and oxygen will oxidize phosphorus.

What is the oxidation number of phosphorus in H3PO4?

We know from part (b) that the oxidation number of the phosphorus atoms in H3PO4 is +5.

What is the charge of na2hpo4?

0
3.1Computed Properties

Property Name Property Value Reference
Formal Charge 0 Computed by PubChem
Complexity 46.5 Computed by Cactvs 3.4.8.18 (PubChem release 2021.05.07)
Isotope Atom Count 0 Computed by PubChem
Defined Atom Stereocenter Count 0 Computed by PubChem

What are the oxidation number of P in NaH2PO4 and S in NaHSO4?

Thus, the oxidation number of P in NaH2PO4 = + 5. 1 1 1 1 4 2 0 6 ( ) ( ) ( ) + + + + + − = = + x x or Thus, the oxidation number of S in NaHSO4 = + 6. 4 1 2 7 2 0 5 ( ) ( ) ( ) + + + − = = + x x or Thus, the oxidation number of P in H4P2O7 = +5. Thus, oxidation number of calcium in CaO2 = +2.

How to calculate oxidation level?

assigning all bonding electrons to the more electronegative atom of each bonded pair.

  • divide the bonding electrons equally between the two bonded atoms.
  • Calculate the total negative charge of the assigned valence electrons plus the inner shell electrons.

    • What are some examples of oxidation numbers?

    An atom of a free element has an oxidation number of .

  • A monatomic ion has an oxidation number equal to its charge.
  • while alkaline earth metals (Group ) always have an oxidation number of .
  • Fluorine has an oxidation number of in all compounds.

    • How do you calculate oxidation states?

    The oxidation number of each atom can be calculated by subtracting the sum of lone pairs and electrons it gains from bonds from the number of valence electrons. Bonds between atoms of the same element (homonuclear bonds) are always divided equally.

    What is phosphorus maximum oxidation number?

    The most important oxidation numbers for phosphorus are -3, +3, and +5 (see table below). Because it is more electronegative than most metals, phosphorus reacts with metals at elevated temperatures to form phosphides, in which it has an oxidation number of -3.