Table of Contents
- 1 What happens to the Na and K channels during depolarization?
- 2 What changes occur to voltage-gated sodium and potassium channels at the peak of depolarization?
- 3 What happens to the voltage during depolarization?
- 4 During which phase of an action potential are voltage-gated K+ channels open while voltage-gated Na+ channels are closed?
- 5 What would happen if the voltage-gated sodium and potassium channels opened further apart?
- 6 What is true about the opening of voltage-gated Na+ and K+ channels?
- 7 What would happen if the voltage-gated sodium and potassium channels opened at the same time?
- 8 Are K channels open during depolarization?
- 9 How is the depolarization of an action potential dependent?
- 10 Where are the inactivation gates of K + channels?
- 11 How does inactivation contribute to the repolarization of the action potential?
What happens to the Na and K channels during depolarization?
During the depolarization phase, the gated sodium ion channels on the neuron’s membrane suddenly open and allow sodium ions (Na+) present outside the membrane to rush into the cell. With repolarization, the potassium channels open to allow the potassium ions (K+) to move out of the membrane (efflux).
What changes occur to voltage-gated sodium and potassium channels at the peak of depolarization?
What changes occur to voltage-gated Na+ and K+ channels at the peak of depolarization? Inactivation gates of voltage-gated Na+ channels close, while inactivation gates of voltage-gated K+ channels open. Inactivation gates of voltage-gated Na+ channels close, while activation gates of voltage-gated K+ channels open.
What happens to the sodium voltage-gated channel when the membrane is depolarized?
As the Na+ moves, or flows, a short distance along the cell membrane, its positive charge depolarizes a little more of the cell membrane. As that depolarization spreads, new voltage-gated Na+ channels open and more ions rush into the cell, spreading the depolarization a little farther.
What happens to the voltage during depolarization?
The membrane begins to depolarize when an external stimulus is applied. The membrane voltage begins a rapid rise toward +30 mV. The membrane voltage starts to return to a negative value. Repolarization continues past the resting membrane voltage, resulting in hyperpolarization.
During which phase of an action potential are voltage-gated K+ channels open while voltage-gated Na+ channels are closed?
As voltage-gated Na+ channels begin to inactivate, the membrane potential stops becoming more positive This marks the end of the depolarization phase of the action potential. Then, as voltage-gated K+ channels open, K+ ions rush out of the neuron, following their electrochemical gradient.
What would happen if the voltage-gated sodium and potassium channels open at the same time?
At the same time, voltage-gated K+ channels open, allowing K+ to leave the cell. As K+ ions leave the cell, the membrane potential once again becomes negative. The diffusion of K+ out of the cell hyperpolarizes the cell, making the membrane potential more negative than the cell’s normal resting potential.
What would happen if the voltage-gated sodium and potassium channels opened further apart?
If they opened up with a longer delay: – too many ions would flow through the membrane, making it take longer for the Na/K pump to reset the ion ratios. – This would prolong the wait time in between nerve impulses.
What is true about the opening of voltage-gated Na+ and K+ channels?
What is TRUE about the opening of voltage-gated Na+ and K+ channels? Voltage-gated K+ channels open more slowly than voltage-gated Na+ channels, even though they are activated at the same time.
What happens when voltage gated sodium channels open?
In the open state, voltage-gated sodium channels form a pore in the cytoplasmic membrane that allows sodium ions to flow into the cell, depolarizing the cell and generating the upstroke of the action potential; however, most sodium channels rapidly transit into the “inactivated” state at depolarized potentials.
What would happen if the voltage-gated sodium and potassium channels opened at the same time?
Are K channels open during depolarization?
After a cell has been depolarized, it undergoes one final change in internal charge. Following depolarization, the voltage-gated sodium ion channels that had been open while the cell was undergoing depolarization close again. The increased positive charge within the cell now causes the potassium channels to open.
What is happening to voltage gated channels at this point in the action potential?
What is happening to voltage-gated channels at this point in the action potential? Na+ channels are inactivating, and K+ channels are opening. Na+ channels are inactivating, and K+ channels are closing.
How is the depolarization of an action potential dependent?
As we have seen, the depolarization and repolarization of an action potential are dependent on two types of channels (the voltage-gated Na + channel and the voltage-gated K + channel). The voltage-gated Na + channel actually has two gates. One is the activation gate, which opens when the membrane potential crosses -55 mV.
Where are the inactivation gates of K + channels?
The inactivation gates of voltage-gated K+ channels close in the node, or segment, that has just fired an action potential. The inactivation gates of voltage-gated Na+ channels close in the node, or segment, that has just fired an action potential.
What causes the membrane potential to become more depolarized?
Suppose a small depolarization causes some of the Na + channels to open. The key point is that the increase in Na + permeability would produce a greater depolarization, which will lead to an even greater number of Na + channels opening and the membrane potential becoming even more depolarized.
How does inactivation contribute to the repolarization of the action potential?
The Na + channels begin to close, even in the continued presence of the depolarization. Inactivation contributes to the repolarization of the action potential. However, inactivation is not enough by itself to account fully for the repolarization.