Table of Contents
- 1 How many minimum 2-input NOR gates are required to make a 2-input OR gate?
- 2 What are minimum number of 2 to 1 multiplexers required to generate a 2-input AND gate and a 2-input EX OR gate?
- 3 How many NOR gates are required to form NAND gate minimum?
- 4 How many NOR gates are required to form NAND gate?
- 5 How much input and output does a demultiplexer need?
- 6 What is the minimum number of NOR gates required to implement an XNOR gate?
- 7 How to use a NOT gate in 2 mux?
- 8 How are 2 input gates used in multiplexer?
How many minimum 2-input NOR gates are required to make a 2-input OR gate?
What is the minimum number of gates required to implement the Boolean function (AB+C)if we have to use only 2-input NOR gates? So, ‘3’ 2-input NOR gates are required.
What are minimum number of 2 to 1 multiplexers required to generate a 2-input AND gate and a 2-input EX OR gate?
Detailed Solution. We need to implement 4 to 1 Mux using 2 to 1 Mux.
How many two input and AND gates are required to realize?
9. How many two input AND gates and two input OR gates are required to realize Y = BD + CE + AB? Explanation: There are three product terms. So, three AND gates of two inputs are required.
What is the minimal number of 2-input NOR gates required to implement an AND gate using only the 2-input NOR gates?
3
Therefore, the minimum number of 2-input NOR gates needed to implement the function is 3.
How many NOR gates are required to form NAND gate minimum?
This is a typical example of a NAND gate. Now, $4$ gates are essential to form NAND gates. For Input: For input it is important to have $2$ NOR gates.
How many NOR gates are required to form NAND gate?
four NOR gates
NAND: It takes four NOR gates to create a NAND gate.
Can a single input NOT gate be designed by a 2 to 1 mux?
NOT gate using 2:1 mux: Figure 13 shows the truth table for a NOT gate. The only inverting path in a multiplexer is from select to output. To implement NOT gate with the help of a mux, we just need to enable this inverting path.
How many 2 1 multiplexer are required to generate a 2 input XOR gate?
This is how a 2:1 multiplexer will implement an XOR gate. Figure 1 below shows the implement of a 2-input XOR gate using a 2:1 Multiplexer. I hope you’ve found this post useful. Let me know what you think in the comments….XOR/XNOR gate using 2:1 MUX.
| A | B | OUT |
|---|---|---|
| 1 | 1 | 1 |
How much input and output does a demultiplexer need?
De-multiplexer: De-multiplexer is a device that has a signal inputs line and multiple line outputs. The given figure has one input and two outputs. Hence it is De-multiplexer.
What is the minimum number of NOR gates required to implement an XNOR gate?
An XNOR gate is made by connecting four NOR gates as shown below. This construction entails a propagation delay three times that of a single NOR gate.
How many NOR gates are required to make an AND gate?
three NOR gates
AND: You need three NOR gates to create an AND gate. The first two are configured as NOT gates, so they invert the inputs. Then the third NOR gate produces a HIGH output if both of the original inputs are HIGH. NAND: It takes four NOR gates to create a NAND gate.
How many MUX are needed to generate two inputs?
To avoid mismatch due to unequal propagation delay second diagram in both of above figures is recommended. What are the minimum number of 2 to 1 MUX required to generate a 2 input AND gate and a 2-input EX or gate? You can build an arbitrary function of two inputs with a 4–1 multiplexor.
How to use a NOT gate in 2 mux?
NOT gate using 2:1 mux: Figure 13 shows the truth table for a NOT gate. The only inverting path in a multiplexer is from select to output. To implement NOT gate with the help of a mux, we just need to enable this inverting path. This will happen if we connect D0 to ‘1’ and D1 to ‘0’.
How are 2 input gates used in multiplexer?
Definition of a multiplexer: A 2^n-input mux has n select lines. It can be used to implement logic functions by implementing LUT (Look-Up Table) for that function. A 2-input mux can implement any 2-input function, a 4-input mux can implement any 3-input, an 8-input mux can implement any 4-input function, and so on.
How to implement a 2 input NAND gate?
2-input NAND gate using 2:1 mux: Figure 1 below shows the truth table of a 2-input NAND gate. If we observe carefully, OUT equals ‘1’ when A is ‘0’. Similarly, when A is ‘1’, OUT is B’. So, if we connect SEL pin of mux to A, D0 pin of mux to ‘1’ and D1 to B’, then it will act as a NAND gate. Figure 1: Truth Table of 2 Input NAND gate.